BFS -5 - Medium - Binary Tree Right Side View - Java

Coding Interviews - Binary Tree Right Side View LeetCode This interview question is commonly asked by companies like Meta Amazon Snap. This problem follows the Binary Tree Level Order Traversal pattern.
We can follow the same BFS approach and use a queue to efficiently traverse in BFS fashion.
The only difference will be that instead of keeping track of all nodes of a level we will only track the last node of that level and append it to our result List which we return at the end once the while loop is completed. Link to previous problem Binary Tree Level order traversal - BFS - Binary Tree Level order traversal 2 - BFS - Binary Tree Zigzag Level Order Traversal - BFS 3 - Binary Tree Average Level order traversal - BFS 4 - Time Complexity - The time complexity of the above algorithm is ON where N is the total number of nodes in the tree.
This is due to the fact that we traverse each node once. Space Complexity - The space complexity of the above algorithm will be ON as we need to return a list containing the level order traversal.
We will also need ON space for the queue.
Since we can have a maximum of N2 nodes at any level this could happen only at the lowest level therefore we will need ON space to store them in the queue. Know more about me LinkedIn -

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